Approximately how many kilowatts does a three-phase, 480-volt AC motor that draws a current of 52 amperes and has a power factor of 88% use?

To determine the kilowatts used by a three-phase, 480-volt AC motor with a current of 52 amperes and a power factor of 88%, we can utilize the formula for calculating power in a three-phase system:

[ P = \sqrt{3} \times V \times I \times PF

]

Where:

• ( P ) is the power in watts,
• ( V ) is the voltage,
• ( I ) is the current in amperes,
• ( PF ) is the power factor (expressed as a decimal).

First, we need to convert the power factor from a percentage to a decimal. An 88% power factor translates to 0.88. Now we can substitute the known values into the formula:

[ P = \sqrt{3} \times 480 , \text{V} \times 52 , \text{A} \times 0.88 ]

Calculating step by step:

1. Calculate ( \sqrt{3} ), which is approximately 1.732.
2. Multiply ( 1.732 ) by ( 480 ) (the voltage): [ 1